x^2-25=(x+5)(x-5)

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Solution for x^2-25=(x+5)(x-5) equation: 



x^2-25=(x+5)(x-5)

We move all terms to the left:

x^2-25-((x+5)(x-5))=0

We use the square of the difference formula

x^2+x^2+25-25=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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